Integrand size = 16, antiderivative size = 185 \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=\frac {d x \left (1-x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {e \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {d x \left (2-7 x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {e \left (1+2 x^2\right )}{6 \left (1+x^2+x^4\right )}-\frac {13 d \arctan \left (\frac {1-2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {13 d \arctan \left (\frac {1+2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {2 e \arctan \left (\frac {1+2 x^2}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {9}{32} d \log \left (1-x+x^2\right )+\frac {9}{32} d \log \left (1+x+x^2\right ) \]
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Time = 0.09 (sec) , antiderivative size = 185, normalized size of antiderivative = 1.00, number of steps used = 19, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.688, Rules used = {1687, 12, 1106, 1192, 1183, 648, 632, 210, 642, 1121, 628} \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=-\frac {13 d \arctan \left (\frac {1-2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {13 d \arctan \left (\frac {2 x+1}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {2 e \arctan \left (\frac {2 x^2+1}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {9}{32} d \log \left (x^2-x+1\right )+\frac {9}{32} d \log \left (x^2+x+1\right )+\frac {d x \left (2-7 x^2\right )}{24 \left (x^4+x^2+1\right )}+\frac {d x \left (1-x^2\right )}{12 \left (x^4+x^2+1\right )^2}+\frac {e \left (2 x^2+1\right )}{6 \left (x^4+x^2+1\right )}+\frac {e \left (2 x^2+1\right )}{12 \left (x^4+x^2+1\right )^2} \]
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Rule 12
Rule 210
Rule 628
Rule 632
Rule 642
Rule 648
Rule 1106
Rule 1121
Rule 1183
Rule 1192
Rule 1687
Rubi steps \begin{align*} \text {integral}& = \int \frac {d}{\left (1+x^2+x^4\right )^3} \, dx+\int \frac {e x}{\left (1+x^2+x^4\right )^3} \, dx \\ & = d \int \frac {1}{\left (1+x^2+x^4\right )^3} \, dx+e \int \frac {x}{\left (1+x^2+x^4\right )^3} \, dx \\ & = \frac {d x \left (1-x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {1}{12} d \int \frac {11-5 x^2}{\left (1+x^2+x^4\right )^2} \, dx+\frac {1}{2} e \text {Subst}\left (\int \frac {1}{\left (1+x+x^2\right )^3} \, dx,x,x^2\right ) \\ & = \frac {d x \left (1-x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {e \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {d x \left (2-7 x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {1}{72} d \int \frac {60-21 x^2}{1+x^2+x^4} \, dx+\frac {1}{2} e \text {Subst}\left (\int \frac {1}{\left (1+x+x^2\right )^2} \, dx,x,x^2\right ) \\ & = \frac {d x \left (1-x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {e \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {d x \left (2-7 x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {e \left (1+2 x^2\right )}{6 \left (1+x^2+x^4\right )}+\frac {1}{144} d \int \frac {60-81 x}{1-x+x^2} \, dx+\frac {1}{144} d \int \frac {60+81 x}{1+x+x^2} \, dx+\frac {1}{3} e \text {Subst}\left (\int \frac {1}{1+x+x^2} \, dx,x,x^2\right ) \\ & = \frac {d x \left (1-x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {e \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {d x \left (2-7 x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {e \left (1+2 x^2\right )}{6 \left (1+x^2+x^4\right )}+\frac {1}{96} (13 d) \int \frac {1}{1-x+x^2} \, dx+\frac {1}{96} (13 d) \int \frac {1}{1+x+x^2} \, dx-\frac {1}{32} (9 d) \int \frac {-1+2 x}{1-x+x^2} \, dx+\frac {1}{32} (9 d) \int \frac {1+2 x}{1+x+x^2} \, dx-\frac {1}{3} (2 e) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+2 x^2\right ) \\ & = \frac {d x \left (1-x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {e \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {d x \left (2-7 x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {e \left (1+2 x^2\right )}{6 \left (1+x^2+x^4\right )}+\frac {2 e \tan ^{-1}\left (\frac {1+2 x^2}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {9}{32} d \log \left (1-x+x^2\right )+\frac {9}{32} d \log \left (1+x+x^2\right )-\frac {1}{48} (13 d) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 x\right )-\frac {1}{48} (13 d) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+2 x\right ) \\ & = \frac {d x \left (1-x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {e \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {d x \left (2-7 x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {e \left (1+2 x^2\right )}{6 \left (1+x^2+x^4\right )}-\frac {13 d \tan ^{-1}\left (\frac {1-2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {13 d \tan ^{-1}\left (\frac {1+2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {2 e \tan ^{-1}\left (\frac {1+2 x^2}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {9}{32} d \log \left (1-x+x^2\right )+\frac {9}{32} d \log \left (1+x+x^2\right ) \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.53 (sec) , antiderivative size = 186, normalized size of antiderivative = 1.01 \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=\frac {1}{144} \left (\frac {12 \left (e+d x+2 e x^2-d x^3\right )}{\left (1+x^2+x^4\right )^2}+\frac {6 \left (d x \left (2-7 x^2\right )+e \left (4+8 x^2\right )\right )}{1+x^2+x^4}-\frac {\left (-47 i+7 \sqrt {3}\right ) d \arctan \left (\frac {1}{2} \left (-i+\sqrt {3}\right ) x\right )}{\sqrt {\frac {1}{6} \left (1+i \sqrt {3}\right )}}-\frac {\left (47 i+7 \sqrt {3}\right ) d \arctan \left (\frac {1}{2} \left (i+\sqrt {3}\right ) x\right )}{\sqrt {\frac {1}{6} \left (1-i \sqrt {3}\right )}}-32 \sqrt {3} e \arctan \left (\frac {\sqrt {3}}{1+2 x^2}\right )\right ) \]
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Time = 0.18 (sec) , antiderivative size = 158, normalized size of antiderivative = 0.85
method | result | size |
default | \(-\frac {\left (\frac {7 d}{3}-\frac {4 e}{3}\right ) x^{3}-6 d \,x^{2}+\left (\frac {20 d}{3}+\frac {e}{3}\right ) x -4 d -2 e}{16 \left (x^{2}-x +1\right )^{2}}-\frac {9 d \ln \left (x^{2}-x +1\right )}{32}-\frac {\left (-\frac {13 d}{2}-16 e \right ) \sqrt {3}\, \arctan \left (\frac {\left (2 x -1\right ) \sqrt {3}}{3}\right )}{72}+\frac {\left (-\frac {7 d}{3}-\frac {4 e}{3}\right ) x^{3}-6 d \,x^{2}+\left (-\frac {20 d}{3}+\frac {e}{3}\right ) x -4 d +2 e}{16 \left (x^{2}+x +1\right )^{2}}+\frac {9 d \ln \left (x^{2}+x +1\right )}{32}+\frac {\left (\frac {13 d}{2}-16 e \right ) \arctan \left (\frac {\left (1+2 x \right ) \sqrt {3}}{3}\right ) \sqrt {3}}{72}\) | \(158\) |
risch | \(-\frac {9 d \ln \left (15457716 d^{2} x^{2}+7237632 e^{2} x^{2}-15457716 d^{2} x -7237632 e^{2} x +15457716 d^{2}+7237632 e^{2}\right )}{32}+\frac {13 \sqrt {3}\, d \arctan \left (\frac {1458 d^{2} x \sqrt {3}}{2187 d^{2}+1024 e^{2}}+\frac {2048 e^{2} x \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}+\frac {729 \sqrt {3}\, d^{2}}{2187 d^{2}+1024 e^{2}}+\frac {1024 e^{2} \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}\right )}{144}-\frac {13 \sqrt {3}\, d \arctan \left (\frac {1269 \sqrt {3}\, d}{567 d +1504 e}-\frac {224 \sqrt {3}\, e}{567 d +1504 e}\right )}{144}-\frac {2 \sqrt {3}\, e \arctan \left (\frac {1458 d^{2} x \sqrt {3}}{2187 d^{2}+1024 e^{2}}+\frac {2048 e^{2} x \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}+\frac {729 \sqrt {3}\, d^{2}}{2187 d^{2}+1024 e^{2}}+\frac {1024 e^{2} \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}\right )}{9}+\frac {2 \sqrt {3}\, e \arctan \left (\frac {1269 \sqrt {3}\, d}{567 d +1504 e}-\frac {224 \sqrt {3}\, e}{567 d +1504 e}\right )}{9}+\frac {13 \sqrt {3}\, d \arctan \left (\frac {1458 d^{2} x \sqrt {3}}{2187 d^{2}+1024 e^{2}}+\frac {2048 e^{2} x \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}-\frac {729 \sqrt {3}\, d^{2}}{2187 d^{2}+1024 e^{2}}-\frac {1024 e^{2} \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}\right )}{144}+\frac {13 \sqrt {3}\, d \arctan \left (\frac {1269 \sqrt {3}\, d}{567 d -1504 e}+\frac {224 \sqrt {3}\, e}{567 d -1504 e}\right )}{144}+\frac {2 \sqrt {3}\, e \arctan \left (\frac {1458 d^{2} x \sqrt {3}}{2187 d^{2}+1024 e^{2}}+\frac {2048 e^{2} x \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}-\frac {729 \sqrt {3}\, d^{2}}{2187 d^{2}+1024 e^{2}}-\frac {1024 e^{2} \sqrt {3}}{3 \left (2187 d^{2}+1024 e^{2}\right )}\right )}{9}+\frac {2 \sqrt {3}\, e \arctan \left (\frac {1269 \sqrt {3}\, d}{567 d -1504 e}+\frac {224 \sqrt {3}\, e}{567 d -1504 e}\right )}{9}+\frac {9 d \ln \left (15457716 d^{2} x^{2}+7237632 e^{2} x^{2}+15457716 d^{2} x +7237632 e^{2} x +15457716 d^{2}+7237632 e^{2}\right )}{32}+\frac {-\frac {7}{24} d \,x^{7}+\frac {1}{3} e \,x^{6}-\frac {5}{24} x^{5} d +\frac {1}{2} e \,x^{4}-\frac {7}{24} x^{3} d +\frac {2}{3} e \,x^{2}+\frac {1}{6} d x +\frac {1}{4} e}{\left (x^{4}+x^{2}+1\right )^{2}}\) | \(671\) |
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Time = 0.29 (sec) , antiderivative size = 278, normalized size of antiderivative = 1.50 \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=-\frac {84 \, d x^{7} - 96 \, e x^{6} + 60 \, d x^{5} - 144 \, e x^{4} + 84 \, d x^{3} - 192 \, e x^{2} - 2 \, \sqrt {3} {\left ({\left (13 \, d - 32 \, e\right )} x^{8} + 2 \, {\left (13 \, d - 32 \, e\right )} x^{6} + 3 \, {\left (13 \, d - 32 \, e\right )} x^{4} + 2 \, {\left (13 \, d - 32 \, e\right )} x^{2} + 13 \, d - 32 \, e\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x + 1\right )}\right ) - 2 \, \sqrt {3} {\left ({\left (13 \, d + 32 \, e\right )} x^{8} + 2 \, {\left (13 \, d + 32 \, e\right )} x^{6} + 3 \, {\left (13 \, d + 32 \, e\right )} x^{4} + 2 \, {\left (13 \, d + 32 \, e\right )} x^{2} + 13 \, d + 32 \, e\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x - 1\right )}\right ) - 48 \, d x - 81 \, {\left (d x^{8} + 2 \, d x^{6} + 3 \, d x^{4} + 2 \, d x^{2} + d\right )} \log \left (x^{2} + x + 1\right ) + 81 \, {\left (d x^{8} + 2 \, d x^{6} + 3 \, d x^{4} + 2 \, d x^{2} + d\right )} \log \left (x^{2} - x + 1\right ) - 72 \, e}{288 \, {\left (x^{8} + 2 \, x^{6} + 3 \, x^{4} + 2 \, x^{2} + 1\right )}} \]
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Result contains complex when optimal does not.
Time = 2.19 (sec) , antiderivative size = 1103, normalized size of antiderivative = 5.96 \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=\text {Too large to display} \]
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Time = 0.27 (sec) , antiderivative size = 137, normalized size of antiderivative = 0.74 \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=\frac {1}{144} \, \sqrt {3} {\left (13 \, d - 32 \, e\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x + 1\right )}\right ) + \frac {1}{144} \, \sqrt {3} {\left (13 \, d + 32 \, e\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x - 1\right )}\right ) + \frac {9}{32} \, d \log \left (x^{2} + x + 1\right ) - \frac {9}{32} \, d \log \left (x^{2} - x + 1\right ) - \frac {7 \, d x^{7} - 8 \, e x^{6} + 5 \, d x^{5} - 12 \, e x^{4} + 7 \, d x^{3} - 16 \, e x^{2} - 4 \, d x - 6 \, e}{24 \, {\left (x^{8} + 2 \, x^{6} + 3 \, x^{4} + 2 \, x^{2} + 1\right )}} \]
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Time = 0.29 (sec) , antiderivative size = 125, normalized size of antiderivative = 0.68 \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=\frac {1}{144} \, \sqrt {3} {\left (13 \, d - 32 \, e\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x + 1\right )}\right ) + \frac {1}{144} \, \sqrt {3} {\left (13 \, d + 32 \, e\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x - 1\right )}\right ) + \frac {9}{32} \, d \log \left (x^{2} + x + 1\right ) - \frac {9}{32} \, d \log \left (x^{2} - x + 1\right ) - \frac {7 \, d x^{7} - 8 \, e x^{6} + 5 \, d x^{5} - 12 \, e x^{4} + 7 \, d x^{3} - 16 \, e x^{2} - 4 \, d x - 6 \, e}{24 \, {\left (x^{4} + x^{2} + 1\right )}^{2}} \]
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Time = 0.15 (sec) , antiderivative size = 185, normalized size of antiderivative = 1.00 \[ \int \frac {d+e x}{\left (1+x^2+x^4\right )^3} \, dx=\frac {-\frac {7\,d\,x^7}{24}+\frac {e\,x^6}{3}-\frac {5\,d\,x^5}{24}+\frac {e\,x^4}{2}-\frac {7\,d\,x^3}{24}+\frac {2\,e\,x^2}{3}+\frac {d\,x}{6}+\frac {e}{4}}{x^8+2\,x^6+3\,x^4+2\,x^2+1}-\ln \left (x-\frac {1}{2}-\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {9\,d}{32}+\frac {\sqrt {3}\,d\,13{}\mathrm {i}}{288}+\frac {\sqrt {3}\,e\,1{}\mathrm {i}}{9}\right )+\ln \left (x+\frac {1}{2}-\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {9\,d}{32}-\frac {\sqrt {3}\,d\,13{}\mathrm {i}}{288}+\frac {\sqrt {3}\,e\,1{}\mathrm {i}}{9}\right )+\ln \left (x-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (-\frac {9\,d}{32}+\frac {\sqrt {3}\,d\,13{}\mathrm {i}}{288}+\frac {\sqrt {3}\,e\,1{}\mathrm {i}}{9}\right )+\ln \left (x+\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {9\,d}{32}+\frac {\sqrt {3}\,d\,13{}\mathrm {i}}{288}-\frac {\sqrt {3}\,e\,1{}\mathrm {i}}{9}\right ) \]
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